#include <stdio.h>


int main()
{
    int n,a,b;
    printf("There are following numbers with 4 digits satisfied condition:\n");
    for(n = 1000;n < 10000;n++)
    {
        a = n/100;
        b = n%100;
        if((a+b)*(a+b) == n)
        {
            printf("%d\t",n);        
        }
    }

    printf("\n");
    return 0;
}
//熊贤豪